YES slay5 is correct the answer is : C. an inscribed angle
Answer:
133.33g
Step-by-step explanation:
Let the:
Mass of 1.2g/cm³ of liquid = x
Mass of 1.8g/cm³ of liquid = y
From our Question above, our system of equations is given as:
x + y = 400........ Equation 1
x = 400 - y
1.2 × x + 1.8 × y = 1.6 × 400
1.2x + 1.8y = 640..... Equation 2
We substitute, 400 - y for x in Equation 2
1.2(400 - y) + 1.8y = 640
480 - 1.2y + 1.8y = 640
- 1.2y + 1.8y = 640 - 480
0.6y = 160
y = 160/0.6y
y = 266.67 g
Solving for x
x = 400 - y
x = 400 - 266.67g
x = 133.33g
Therefore, the mass of the liquid of density 1.2g/cm³ is 133.33g
Angle BOC = 120
PROOF
Angle A + Angle B + Angle C = 180
So, Angle B + Angle C = 120 (Angle A = 60)
Now 1/2 (Angle B + Angle C) = 60
1/2 Angle B + 1/2 Angle C = 60..............i
In triangle BOC
1/2 Angle B + 1/2 Angle C + Angle BOC =180
(BO and CO are angle bisectors)
Or 60 + Angle BOC = 180 (using i)
OR ANGLE BOC = 120
C since it is a positive 1640 and that is what you are looking for
