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lozanna [386]
3 years ago
12

Write the sentence as a conditional statement. Two parallel lines lie in the same plane. If two lines are parallel, then the lin

es lie in the same plane. If two lines lie in the same plane, then the lines are parallel.
Mathematics
1 answer:
olga nikolaevna [1]3 years ago
6 0
<h2>Answer:</h2>

The conditional statement is:

  • If two lines are parallel then they lie in the same plane.
<h2>Step-by-step explanation:</h2>

We know that a conditional statement is the statement which is written in the form of:

        If  p then q  i.e.  p → q

where p is the hypothesis of the statement.

and q is the conclusion  of the statement which is based on the hypothesis.

Here we are given a statement as:

 Two parallel lines lie in the same plane.

i.e. the hypothesis of the conditional statement is:

Two lines are parallel.

and conclusion is: They will lie in the same plane

( Because if two lines lie in the same plane then we can't conclude that they will be parallel )

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Answer:

V = 63π / 200  m^3

Step-by-step explanation:

Given:

- The function y = f(x) is revolved around the x-axis over the interval [1,6] to form a spherical surface:

                                 y = √(42*x - x^2)

- The surface is coated with paint with uniform layer thickness t = 1.5 mm

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The volume of paint needed

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- Let f be a non-negative function with a continuous first derivative on the interval [1,6]. The Area of surface generated when y = f(x) is revolved around x-axis over the interval [1,6] is:

                           S = 2*\pi \int\limits^a_b { [f(x)*\sqrt{1 + f'(x)^2} }] \, dx

- The derivative of the function f'(x) is as follows:

                            f'(x) = \frac{21-x}{\sqrt{42x-x^2} }

- The square of derivative of f(x) is:

                            f'(x)^2 = \frac{(21-x)^2}{42x-x^2 }

- Now use the surface area formula:

                           S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2} *\sqrt{1 + \frac{(21-x)^2}{42x-x^2 } }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+(21-x)^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{42x-x^2+441-42x+x^2} }] \, dx\\\\S = 2*\pi \int\limits^6_1 { [\sqrt{441} }] \, dx\\S = 2*\pi \int\limits^6_1 { 21} \, dx\\\\S = 42*\pi \int\limits^6_1 { dx} \,\\\\S = 42*\pi [ 6 - 1 ]\\\\S = 42*5*\pi \\\\S = 210\pi

- The Volume of the pain coating is:

                           V = S*t

                           V = 210*π*3/2000

                          V = 63π / 200 m^3

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