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Elis [28]
3 years ago
12

Write the quadratic equation whose roots are −2 and −5, and whose leading coefficient is 4.

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

Step-by-step explanation:

quadratic equation is 4(x+2)(x+5)=0

4(x²+5x+2x+10)=0

4x²+28x+40=0

Anni [7]3 years ago
7 0

Answer:

f(x) = 4(x+2)(x+5)

Step-by-step explanation:

The quadratic function is

f(x) = a(x-b1)(x-b2)  where a is a coefficient and b1 and b2 are the zeros

f(x) = a(x --2)(x--5)

f(x) = a(x+2)(x+5)

The leading coefficient is a and we know a =4

f(x) = 4(x+2)(x+5)

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What number is it that, when multiplied by 18,27,36,45,54,63,72,81, or 99, gives a product in which the first and last figures a
allsm [11]

The given multipliers are factors of 9, the possible number will have 1 as first and last digit which gives the number as 101

<h3>How can the correct number be found?</h3>

The given numbers are;

18, 27, 36, 45, 54, 63, 72, 81, 99

Given that the first and the last figures are those of the multipliers, we have;

The first and last and last digit of the number can be 1, which gives;

Possible numbers includes; 11 and 101

By trying the possible numbers, the difference found is presented as follows;

99 × 11 = 1089 (The first and the last digit are not the same as the multiplier)

  • 99 × 101 = 9999 (First and last digit are not the same as the multiplier)

90 × 11 = 990

90 × 101 = 9090

The correct option is therefore 101

  • The number is 101

Learn more about multiplication of numbers here:

brainly.com/question/83239

#SPJ1

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Help with hw please I’ll give brainliest
Ymorist [56]
The first one is B
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