All categories

3 years ago

Write the quadratic equation whose roots are −2 and −5, and whose leading coefficient is 4.

Mathematics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

Step-by-step explanation:

quadratic equation is 4(x+2)(x+5)=0

4(x²+5x+2x+10)=0

4x²+28x+40=0

Anni [7]3 years ago

7 0

Answer:

f(x) = 4(x+2)(x+5)

Step-by-step explanation:

The quadratic function is

f(x) = a(x-b1)(x-b2) where a is a coefficient and b1 and b2 are the zeros

f(x) = a(x --2)(x--5)

f(x) = a(x+2)(x+5)

The leading coefficient is a and we know a =4

f(x) = 4(x+2)(x+5)

You might be interested in

How can the distributive property be used to find 4 x 875? draw an array.

nika2105 [10]

Easy here
(4x800)+(4x70)+(4x5)

8 0

3 years ago

Find the lateral area of an equilateral triangular prism if the area of each lateral face is 10 square centimeters

saw5 [17]

The face dimensions are all the same, so the 3 lateral faces each have the same area. The lateral area is
3·(10 cm²) = 30 cm²

3 0

3 years ago

At the beginning of the week, Tideland Manufacturing had an inventory of 60,000 screws. This week they received a shipment of 30

Paraphin [41]

Answer:

40,000

Step-by-step explanation:

You just add 60,000 and 30,000 which makes 90,000 and subtract it with the 50,000 then which equals to 40,000. you don't need to rate me.

7 0

3 years ago

Current government spending to fund public schools is about 6×1011 dollars per year. The average cost nationally for a student t

NeX [460]

60000000 students can attend public schools with the current funding

Solution:

Given that Current government spending to fund public schools is about $6 \times 10^{11}$ dollars per year

The average cost nationally for a student to attend a public school for a year is about $10,000

To find: number of students can attend public schools with the current funding

$\text{ current funding } = 6 \times 10^{11} \text{ dollars}$

$\text{ average cost for 1 student } = 10000 \text{ dollars }$

Therefore,

$\text{ number of students } = \frac{\text{ current funding }}{\text{ average cost of 1 student}}$

Substituting the values we get,

$\text{ number of students } = \frac{6 \times 10^{11}}{10000}\\\\\rightarrow \frac{6 \times 10^{11}}{10000} = \frac{6 \times 10^{11}}{10^4}\\\\\rightarrow \frac{6 \times 10^{11}}{10^4} = 6 \times 10^{11-4} = 6 \times 10^7\\\\\rightarrow 6 \times 10^7 = 60000000$

Thus 60000000 students can attend public schools with the current funding

6 0

3 years ago

What is 234764-456+54

lys-0071 [83]

It is 234362 ----%%&&:"%

4 0

3 years ago

Read 2 more answers