All categories

2 years ago

How do i do sohcahtoha

Mathematics

1 answer:

DochEvi [55]2 years ago

8 0

Answer:

you mean trigonometry i'm assuming

but essentially:

soh = sin theta (the angle) = opposite length/hypotenuse length

cah = cos theta (angle) = adjacent length/hypotenuse length

toa = tan theta (angle) = opposite length/adjacent length

Step-by-step explanation:

You might be interested in

Find an expression for the nth term ( tn ) in each of the following sequences:

Alexandra [31]

Answer:

The expression for the nth term is Tn = 8n -7

Step-by-step explanation:

Here, we are to find an expression for the nth term of the sequence.

Mathematically, the nth term of an arithmetic sequence can be expressed as;

Tn = a + (n-1)d

for T2, the equation is

a + d = 9

for T4, the equation is

a + 3d = 25

we can substitute the equation of T2 into T4 but we first need to rewrite T4

a + d + 2d = 25

9 + 2d = 25

2d = 25 -9

2d = 16

d = 16/2

d = 8

now since a + d = 9

a = 9-d

a = 9-8

a = 1

So the expression for the nth term would be;

1 + (n-1)8

1 + 8n - 8

= 8n -8+1

= 8n -7

6 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

2 years ago

Read 2 more answers

Brian pays £275.23 a year on his car insurance.

Roman55 [17]

Hope this helps!!!!!!!!!!

5 0

2 years ago

What is 1 4/5×6 equal too

AlekseyPX

Answer: 10 4/5

Convert the mixed numbers to improper fractions

Use the algebraic formula for addition of fractions:

a/b + c/d = (ad + bc) / bd

Reduce fractions and simplify if possible

8 0

3 years ago

Does this graph represent a function? Why or why not?

qaws [65]

The answer to this question is B

6 0

2 years ago