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3 years ago

What property is this? -5 + 5 = 0

Mathematics

1 answer:

Elden [556K]3 years ago

3 0

Answer:

Inverse Property of Addition

Step-by-step explanation:

Any problems that will go into the inverse property of addition must equal 0. In this case, the equation above shows two of the same numbers with opposite signs in which that will equal to zero.

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The dimensions of the computer screen are modeled by the equation x2 + (x – 4)2 = 202. What is the value of x, the length of the

Mars2501 [29]

Answer:

x = 11.85

Step-by-step explanation:

x^2+(x-4)^2=202

x^2+(x-4)(x-4)=202

x^2 + x^2 - 4x - 4x + 16 = 202

2x^2 - 8x + 16 = 202

2x^2 - 8x - 186 = 0

Apply the quadratic equation and you'll get x as:

x=11.85 or x=-7.85

x cannot be negative

therefore x = 11.85

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2 years ago

What is the first step to solve the equation 16x-21 = 52?

Makovka662 [10]

Answer:

2) Add 21 to both sides

Step-by-step explanation:

When solving $16x-21=52$ for $x$ , our goal to isolate $x$ such that we have $x$ set equal to something.

Therefore, we want to start by adding 21 to both sides. This leaves us with $16x=73$ and we are one step closer to isolating $x$ .

8 0

3 years ago

Read 2 more answers

The vertices of a trapezoid are located at (1, 2), (3, 1), (3, 5), (1, 4). The trapezoid is translated 4 units to the right. Wha

padilas [110]

Answer:

Suppose that we have a given point (x, y)

If we translate this point N units to the right, then the new coordinates of the point are:

(x + N, y)

Ok, now if we know that the vertices of the trapezoid are:

(1, 2), (3, 1), (3, 5), (1, 4)

And we move the whole figure 4 units to the right, then all the vertices are moved 4 units to the right.

Then the new vertices of the figure will be:

(1 + 4, 2) = (5, 2)

(3 + 4, 1) = (7, 1)

(3 + 4, 5) = (7, 5)

(1 + 4, 4) = (5, 4)

Then the coordinates of the image of the trapezoid (of the new vertices) are:

(5, 2), (7, 1), (7, 5), (5, 4)

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3 years ago

"let v = r 2 with the usual addition and scalar multiplication defined by k(u1, u2) = (ku1, 0). determine which of the five axio

expeople1 [14]

Let $\mathbf u\in\mathbb R^2$ , where

$\mathbf u=(u_1,u_2)$

and let $k\in\mathbb R$ be any real constant.

Given this definition of scalar multiplication, we can see right away that there is no identity element $e$ such that

$e\mathbf u=\mathbf u$

because

$e\mathbf u=e(u_1,u_2)=(eu_1,0)\neq(u_1,u_2)=\mathbf u$

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3 years ago

Solve for p -6p+7=3(2p-3)-4(-10+4p

ozzi

p-6p+7=3(2p-3)-4(-10+4p

We move all terms to the left:

p-6p+7-(3(2p-3)-4(-10+4p)=0

We add all the numbers together, and all the variables

p-6p-(3(2p-3)-4(4p-10)+7=0

We add all the numbers together, and all the variables

-5p-(3(2p-3)-4(4p-10)+7=0

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3 years ago