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Monica [59]
4 years ago
5

How does acceleration values differ mathematically from deceleration values?

Physics
1 answer:
Serggg [28]4 years ago
8 0
If a problem says the acceleration is some positive value than solve using that value, a negative acceleration is said to be deceleration. E.g. a car decelerating at 10 m/sec can be said to be accelerating at -10 m/sec.

If a problem states decelerates at A, then use -A for acceleration in the classic equations which are for acceleration. If a problem says accelerates at a negative value like -A the use -A as the value for acceleration, it can also be said to be decelerating at A.
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Answer:

1.66666666667

Explanation:

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Explanation:

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What does the ideal gas law allow a scientist to calculate that the other gas laws do not?
Anvisha [2.4K]

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3 years ago
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A 1000-n weight is hanging from a 2.0 m long aluminum rod. A 500-n weight is hanging from a 1.0 m long aluminum rod. The two alu
Hunter-Best [27]

Answer:

Both rod have the same tensile stress

Explanation:

Given information,

The weight first rod, W_{1} = 1000 N

The length of first rod, l_{1} = 2.0 m

The weight second rod, W_{2} = 500 N

The length of second rod, l_{2 = 1.0 m

The equation of tensile stress, σ = \frac{F}{A}

where

σ = tensile stress (N/m^{2} or Pa)

F = Force (N)

A = Area (N/m^{2} or Pa)

so

σ1 =  \frac{W_{1} }{A_{1} }, A = 2πl

    = \frac{1000}{2\pi(2) }

    = \frac{250}{\pi } N/m^{2}

now calculate σ2

σ2 =  \frac{W_{2} }{A_{2} }

     = \frac{500}{2\pi(1) }

     = \frac{250}{\pi } N/m^{2}

σ1/σ2 = \frac{250}{\pi } / \frac{250}{\pi }

σ1/σ2 = 1

σ1 = σ2

Hence, the tensile stress of first and second rod are the same.

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4 years ago
A pendulum has 366 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o
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