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AlladinOne [14]
2 years ago
7

Suppose you had two magnets, who were attracted to each other, and you brought them together. Then took them apart by separating

them from one another a short distance and then long distance. What would happen to electromagnetic force between the two objects from start to finish?
Physics
1 answer:
IgorLugansk [536]2 years ago
8 0

Answer:4. Two charged objects have a repulsive force of 0.080 N. If the distance separating the objects is tripled, then what is the new force? Explanation: The electrostatic force is inversely related to the square of the separation distance.

Explanation:

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A system of releases 125kJ of heat while 104kJ of work is done in the system. Calcilate the change om imternal energy (in kJ)
artcher [175]

Answer:

DU = 21 KJ

Explanation:

Given the following data;

Quantity of heat = 125 KJ

Work = 104 KJ

To find the change in internal energy;

Mathematically, the change in internal energy of a system is given by the formula;

DU = Q - W

Where;

DU is the change in internal energy.

Q is the quantity of energy.

W is the work done.

Substituting into the formula, we have;

DU = 125 - 104

DU = 21 KJ

4 0
2 years ago
When a vapor condenses to a liquid, an amount of thermal energy (Q
mina [271]

Answer:

true

Explanation:

I did this unit for science

6 0
2 years ago
If earth had no atmosphere , would a falling object ever reach terminal velocity?
Bas_tet [7]
The right answer is no.
6 0
3 years ago
If a leaf falls from a tree, has work been done on the leaf? Explain.
mihalych1998 [28]

Answer:

Hope this helps!

5 0
3 years ago
calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention o
leonid [27]

Answer:

Force = 0.0047175\ N

Explanation:

Given

T = 0.075N/m --- Surface Tension

r = 0.01m --- Radius

Required

Determine the required force

First, we calculate the circumference (C) of the circular plate

C= 2\pi r

C= 2 * \frac{22}{7} * 0.01m

C= \frac{2 * 22 * 0.01}{7}m

C= \frac{0.44}{7}m

C= 0.0629 m

The applied force is then calculated using;

Force = C * T

Force = 0.0629m * 0.075N/m

Force = 0.0047175\ N

8 0
3 years ago
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