M = 1.2*

+ 0.13
If M = 19,
ln((19-0.13)/1.2)/.25 = t
All the side measures of ΔDOG will have the same relationship to their corresponding ΔSLB measures that DO has to SL.
OG/LB = DO/SL
OG/4 = 5/3
OG = 20/3
DG/SB = DO/SL
DG/5 = 5/3
DG = 25/3
In summary,
OG = 20/3 = 6 2/3
DG = 25/3 = 8 1/3
So he has $40 in the bank. So first he buys gas for $40 , then writes a check for 64.75. So it would be 40-40-64.75= -64.75
The answer is six equal sized links because two, three, and six, are all factors of six.
Answer:
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 64 - 1 = 63
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 63 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.387
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 2.99 - 0.02 = 2.97 liters
The upper end of the interval is the sample mean added to M. So it is 2.99 + 0.02 = 3.01 liters
The 98% confidence interval estimate of the true average amount of soft drink in each bottle is between 2.97 liters and 3.01 liters.