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sweet-ann [11.9K]
3 years ago
11

the measures of 2 angles are (5x+24) and (9x-7). what is the value of x if these angles are congruent?

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0

Hello!

We assign (5x + 24) to angle one and (9x - 7) to angle two. If these angles are congruent, then angle one is equal to angle two. To find the value of x, you need to create and equation as follows: 5x + 24 = 9x - 7 and find the value of x like a normal algebraic equation.

5x + 24 = 9x - 7 (subtract 5x from both sides)

24 = 4x - 7 (add 7 to both sides)  

31 = 4x (divide 4 to both sides)

x = 31/4

Therefore, the value of x is equal to 31/4.

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If EF = (7x + 8), FG = (9x - 8), and EG = 128, find the values of x, EF, and FG.
katrin [286]

Answer:

Answer:

x = 3.3

EF = 31.1

FG = 21.7

Step-by-step explanation:

Step-by-step explanation:

4 0
3 years ago
Can someone help me with this. I tried to total all them up with 180 but none of the answers i got match the ones from the riddl
Vladimir79 [104]

Answer:

9. x=102

10. x=56

11. x=104

12. x=138

Step-by-step explanation:

9.  In this problem, they are alternate exterior angles, meaning they are the same value.  x=102

10.  x is a corresponding angle, meaning they are the same. x=56

11. There are consecutive interior angles. The sum of these two angles is 180. to find x, subtract 76 from 180.  180-76 = 104  x = 104

12. These two angles are verticle angles, meaning they are equivalent. x = 138

6 0
3 years ago
Can someone help me with this x+5=13 ​
kkurt [141]

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8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for x<br>a.81<br>b.41<br>c.1681
Jlenok [28]
A=9 , b=40

Pythagorean theorem
a^2+b^2=x^2 \\\\ x=\sqrt{a^2+b^2}=\sqrt{9^2+40^2}=\sqrt{81+1600}=\sqrt{1681}=\sqrt{41^2}=41
5 0
3 years ago
it’s sad when I help people because they can’t do the same thing for me pls just for once answer this pls :(((((((
yKpoI14uk [10]

Answer:

D

Step-by-step explanation:

It compares two values.

Hope this helps!

3 0
2 years ago
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