A study finds that out of every 400 babies born in the world, 28 have some kind of major birth defect. The simplest way to assign random numbers to conduct a simulation based on this statistic is to use 00-06 (7%) to indicate the babies with birth defects.
<h3>What is the rationale for the above?</h3>
Note that the total number of births is: 400
Total number of defective babies = 28
Hence, the fraction or ratio of this is:
28/400
= 7/100
= 7%.
This also means that 07-99 (93%) will represent the babies without birth defects.
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The answer is B.24x^6-18x^5=6x^5(4x-3)
Answer:
8 cm
Step-by-step explanation:
This is a problem of Standard Normal distribution.
We have mean= 12 grams
Standard Deviation = 2.5 grams
First we convert 8.5 to z score. 8.5 converted to z score for given mean and standard deviation will be:

So, from standard normal table we need to find the probability of z score to be less than -1.4. The probability comes out to be 0.0808
Thus, the <span>
probability that the strawberry weighs less than 8.5 grams is 0.0808</span>
Answer:
Position 12.
Step-by-step explanation:
It will be n the center of the bottom 23 numbers ( when the data is arranged in ascending order).
That is in position 12.