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spayn [35]
3 years ago
15

Please help?? I have an exam tomorrow

Mathematics
2 answers:
sergey [27]3 years ago
5 0

Answer:

Step-by-step explanation:

astra-53 [7]3 years ago
4 0

Answer:

Step-by-step explanation:

x² - 5xy + 6y² = x² - 3xy - 2xy + 6y²

                      = x(x  - 3y) - 2y(x - 3y)

                      = (x - 3y)(x -2y)

x² - 4xy + 3y² = x² -xy - 3xy + 3y²

                      = x(x - y) - 3y(x - y)

                      = (x - y)(x - 3y)

x² - 3xy + 2y² = x² - xy - 2xy + 2y²

                      = x(x - y) - 2y(x - y)

                     = (x - y)(x - 2y)

Least common denominator = (x-y)(x - 2y)(x - 3y)

RHS = \frac{1*(x-y)}{(x-3y)(x-2y)*(x-y)}+\frac{a*(x-2y)}{(x-y)(x-3y)*(x-2y)}+\frac{1*(x-3y)}{(x-y)(x-2y)*(z-3y)}\\\\= \frac{x- y + ax - 2ay +x -3y}{(x-y)(x-2y)(x-3y)}\\\\= \frac{2x -4y +ax - 2ay}{ x^{3}-5x^{2}y+8xy^{2}-4y^{3}}

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8 0
3 years ago
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LiRa [457]
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Now consider triangles AOD and BCD:
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6 0
4 years ago
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MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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joja [24]

Answer:

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7 0
3 years ago
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