In ΔOPQ, o = 5.9 cm, q = 5.5 cm and ∠Q=142°. Find all possible values of ∠O, to the nearest 10th of a degree.
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Answer: The slant height of the cone is 65.6 m
Step-by-step explanation:
Given: The diameter of a cone = 10 m
Surface area of cone = 190.6 m²
To find: Slant height
Diameter of cone = 10 m
Therefore Radius of cone =
As we know that surface area of a cone is given by
Where S.A. is surface area , r is the radius of cone and l is the slant height of the cone.
Let Slant height = l
So we have
Hence the slant height of the cone is 65.6 m