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3 years ago

Please solve it

Mathematics

1 answer:

Marizza181 [45]3 years ago

4 0

XD no sé que decir E=mc2 lo siento.

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navik [9.2K]

Answer:

£2,121.8

Step-by-step explanation:

Given the following;

Principal P = £2000

Rate r = 3%

Time t = 2 years

n = 1 (time of compounding)

Using the compound interest formula;

A = P(1+r)^t

A = 2000(1+0.03)^2

A = 2000(1.03)^2

A = 2000(1.0609)

A = 2,121.8

hence the amount that will be in his account after 2 years is £2,121.8

6 0

3 years ago

Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

3 0

4 years ago

3х +5= 23 what is x equal

mihalych1998 [28]

Answer:

x=6

Step-by-step explanation:

3х +5= 23

Subtract 5 from each side

3х +5-5= 23-5

3x = 18

Divide each side by 3

3x/3 =18/3

x = 6

3 0

3 years ago

Mercury has a density of 13.6 g/cm^3 . What volume of mercury will have a mass of 47 grams? It’d be very helpful if someone coul

kondaur [170]

Density = mass / volume

Givens

Density = 13.6 grams / cm^3

mass = 47 grams.

Solve

D = m/v

13.6 = 47 / volume Multiply by volume

13.6 * volume = 47 Divide by 13.6

volume = 47 / 13.6

Volume = 3.46 ccs

6 0

4 years ago

What is the solution to the system of equations?

tresset_1 [31]

A system of equation are a set or collection of equations altogether at once

6 0

4 years ago