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Nadusha1986 [10]
2 years ago
9

A number c minus 4.3 is no less than 16. write this word sentence as an inequality.

Mathematics
1 answer:
aksik [14]2 years ago
6 0

Answer:

c - 4.3 > 16

(hope this helps)

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Two times the sum of nine and a number is the opposite of 9.
marshall27 [118]
18 that question is confusing so I guessed sorry dude
8 0
3 years ago
Draw a rectangular fraction model to find the sum. Simplify your answer, if possible
stiv31 [10]
Just draw a rectangle and hope it's right
8 0
3 years ago
Simplify the expression. 34 • 3
bekas [8.4K]

Answer:

102

Step-by-step explanation:

34*3=102

the dot in the middle is just another way to say that it is multiplying the equation so it just mean that your are multiplying 34 by 3 which is 102

3 0
3 years ago
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
2 years ago
Which numbers have a digit in the ones place that is 1/10 the value of the digit in the tens place
liq [111]

Answer:

4,099  and 5,011

Step-by-step explanation:

This problem can be solved by taking options one by one.

Option (1) : 4,099  

Digit in ones place = 9

The value of the digit in tens place = 90

\dfrac{9}{90}=\dfrac{1}{10}. It is correct.

Option (2) : 4,110

Digit in one places = 0

The value of the digit in tens place = 10

It is incorrect.

Option (3) : 5,909

Digit in one places = 9

The value of the digit in tens place = 0

It is again incorrect.

Option (4) : 5,011

Digit in one places = 1

The value of the digit in tens place = 10

\dfrac{1}{10}. It is correct.

Hence, in option (a) and (d), the he ones place is 1/10 the value of the digit in the tens place.

7 0
3 years ago
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