Question

The sum of a number and its inverse is 3 29/52 . Find the number?

Answer 1

Answer:

x1=

104

329+

329

2

−10816

x2=\frac{329-\sqrt{329^{2} -10816} }{104}x2=

104

329−

329

2

−10816

The sum of a number and its inverse is 3 29/52. Find the number?

x+1/x=329/52

x+1/x-329/52=0

solve the fraction

(\frac{(52x^{2} +52-329x)}{52x} =0

52x

(52x

2

+52−329x)

=0

52x^{2} +52-329x=052x

2

+52−329x=0

52x^{2} -329x+52=052x

2

−329x+52=0

using the quadratic formular

(-b+-√b^2-4ac) / 2a(−b+−√b

2

−4ac)/2a

x=\frac{329+-\sqrt{(329)^{2} -4*52*52} }{2*52}x=

2∗52

329+−

(329)

2

−4∗52∗52

x1=\frac{329+\sqrt{329^{2}-10816 } }{104}x1=

104

329+

329

2

−10816

x2=\frac{329-\sqrt{329^{2} -10816} }{104}x2=

104

329−

329

2

−10816