Answer:
bjukvbbvuhbbbuyvbuybgvuybvgtbvytvygvgvhvmhvghvcjygcnhmStep-by-step explanation:
A.
Find the dimensions of the original painting.
Since the scale is 1 in : 40 cm
2 in ( 40 cm / 1 in) = 80 cm
1.5 in ( 40 cm / 1 in) = 60 cm
80 cm by 60 cm
B.
Find the area of the original painting.
<span>A = 80
cm x 60 cm = 4800 sq cm</span>
C.
Since 1 inch is 2.54 cm, find the dimensions of the original painting in
inches.
80 cm ( 1 in / 2.54 cm) = 31.5 in
60 cm ( 1 in / 2.54 cm) = 23.6 in
D,
Find the area of the original painting in square inches.
A = 31.5 in x 23.6 in = 743.4 sq in
<span> </span>
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Answer:
True
Step-by-step explanation:
The given statement is true as a common approach to keeping a record of each customer's account receivable is to use a subsidiary accounts receivable ledger. An account's receivable subsidiary ledger is an accounting ledger that shows the transaction and payment history of each customer to whom the business extends credit.
Answer:
Thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F
Thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F
Step-by-step explanation:
If the temperature is x° F below 0° F then the thermometer reading is -x° F
It is given that the Lowest temperature recorded at Oymyakon in Russai was 96.2°F below 0°F
So the thermometer reading of the lowest recorded temperature at Oymyakon was -96.2° F
Also it is given that the Lowest temperature recorded at Prospect Creek in Alaska was 80°F below 0° F
So the thermometer reading of the lowest recorded temperature at Prospect Creek was -80° F
