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3 years ago

Please help me please !!

Mathematics

1 answer:

sweet [91]3 years ago

8 0

Answer:

Acute

Step-by-step explanation:

7² + 9² ? 11²

49 + 81 ? 121

130 is greater than 121, so it is an acute triangle

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Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2⁄3 + y2⁄3 = 4, −3 3 , 1

STatiana [176]

The complete question is

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. $x^\frac{2}{3} + y^\frac{2}{3} = 4$ , $( -3\sqrt{3} ,1)$

Answer:

Equation of tangent is y = $\frac{1}{\sqrt{3} }$ x + 4

Step-by-step explanation:

We are given the equation

$x^\frac{2}{3} + y^\frac{2}{3} = 4$ ,

upon differentiating

d( $x^\frac{2}{3} + y^\frac{2}{3} = 4$ ) /dx = d(4)/dx

$\frac{2}{3}x^-\frac{1}{3 } + \frac{2}{3}y^ -\frac{1}{3} dy/dx = 0$

dy/dx = $-x^\frac{1}{3} /y^-\frac{1}{3}$ = $-y^\frac{1 }{3}/ x^\frac{1}{3}$

upon substituting the values (x, y)= $( -3\sqrt{3} ,1)$

dy/dx = $\frac{1}{\sqrt{3} }$

equation of the tangent

y - 1 = $\frac{1}{\sqrt{3} }$ ( x- (- $3\sqrt{3}$ ))

y = $\frac{1}{\sqrt{3} }$ x + 4

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Answer:

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Step-by-step explanation:

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