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jekas [21]
3 years ago
11

A pool can be filled by one pipe in 6 hours and by a second in 12 hours . How long will it take using both pipes to fill the poo

l?
Mathematics
2 answers:
kolezko [41]3 years ago
6 0

Answer:

4 hours

Step-by-step explanation:

Part of the pool filled by first pipe in an hour = 1/6

Part of the pool filled by second pipe in an hour = 1/12

Part of the pool filled by first pipe and second pipe in an hour = 1/6 +1/12

             =\frac{1*2}{6*2}+\frac{1}{12}\\= \frac{2}{12}+\frac{1}{12}\\\\=\frac{3}{12}\\\\=\frac{1}{4}

Time taken by both the pipes to fill the pool = 4 hours

erica [24]3 years ago
3 0
One pipe = 1/6 of the pool in one hour
Second pipe = 1/12 of the pool in one hour
Let x be the time
Make them equal to 1 (total of pool)
1/6(x) + 1/12(x) = 1
Make non fraction by multiplying by 12
2x + 1x = 12
3x = 12, x = 4
It would take 4 hours
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