Question

What's the domain and range function for y=(x-12)^2+11

Answer 1

Answer:

Step-by-step explanation:

There is no restriction upon x so the domain is all real numbers

x=(-oo, +oo)

y has a minimum value when x=12 and y=11. Any other value of x increases the value of y. So the range is all real numbers greater than or equal to 11.

y=[11, +oo)

Answer 2

Answer:y = x 2 − 12 x The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. Interval Notation: ( − ∞ , ∞ ) Set-Builder Notation: { x | x ∈ R } The range is the set of all valid y values. Use the graph to find the range. Interval Notation: [ − 36 , ∞ ) Set-Builder Notation: { y | y ≥ − 36 } Determine the domain and range. Domain: ( − ∞ , ∞ ) , { x | x ∈ R } Range: [ − 36 , ∞ ) , { y | y ≥ − 36 }

Step-by-step explanation: