Answer: Okay, the answer is x^2/68+(y+3)^2/17=1.
Step-by-step explanation: Step. 1 Complete the square for 4y^2+24y: 4(y+3)^2−36.
Step 2. You’ll need to substitute 4(y+3)^2−36 for 4y^2+24y in the equation x^2+4y^2+24y=32: x^2+4(y+3)^2–36=32.
Step 3. So you’ll need to move –36 to the right side of the equation by adding 36 to the both sides: x^2+4(y+3)^2=32+36.
Step 4 You add 32 and 36: x^2+4(y+3)^2=68.
Step 5. You divide each term by 68 to make the right side equal to one: x^2/68+4(y+3)^2/68=68/68.
And step 6. You’ll need to simplify each term in the equation in order to set the right side equal to 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1: x^2/68+(y+3)^2/17=1. I hope you download Math-way app to calculate this ellipse in standard form to be extremely helpful, please mark me as brainliest, and have a great weekend! :D
OPTION C is the correct answer.
Hope it helps you.
In most approximate way it can never be the area of the circle (Accurate area)
This is why because after creating base lines of each triangle it forms an inscribed polygon .
- Some little spaces left over each side or b_n
So
h is already approaching to r
- and b_1+b_2..b_n is approaching to the perimeter i.e 2πr
Option B
Median Example
For the data set 1, 1, 2, 5, 6, 6, 9 the median is 5.
For the data set 1, 1, 2, 6, 6, 9 the median is 4.
