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d1i1m1o1n [39]
2 years ago
7

14. What, if any, is a real solution to 5x +1 +9 - 3? 1 C D. There is no real solution.

Mathematics
1 answer:
lesya692 [45]2 years ago
6 0

I believe the question is:

What is the solution to 5x + 1 +9 - 3

In this case, we solve for X.

5x + 1 + 9 - 3

5x + 10 - 3

5x + 7

5x = -7

x = -7/5

Unfortunately, It is not one of the answer choices it looks like.

Maybe you should reword your question but hopefully this is correct.

If you meant to say 5x+1 + 9 < 3 --> 5x + 10 < 3 --> 5x < -7 --> x < -7/5

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Step-by-step explanation:

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7 0
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How much water do you need to add to make each concentration?<br> 1% sugar syrup using 12 g sugar
yulyashka [42]

Answer:

1188 grams of water

Step-by-step explanation:

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6 0
2 years ago
What is the square root of this problem?—-
musickatia [10]
<h2>Answer</h2>

The answer to this question is 0.9

<h2>Explanation</h2>

We know that

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Then sequre of 0.9 will be

0.9^2 = 0.81

So,

b = \sqrt{ 0.81}

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Exponent and square root cancel out each other

So, the answer is 0.9.


4 0
3 years ago
The average load is $350. It comes with an average of 15%, which is compounded every two weeks. What is the average amount for a
morpeh [17]
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7 0
3 years ago
A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la
andriy [413]

Answer:

Initial value is \frac{1}{2}.

Step-by-step explanation:

Let us assume that the exponential function is f(x) = a(b)^{x} ...... (1)

Now, the point (0,\frac{1}{2}) will satisfy the above equation.

Now, this point on the graph of the exponential function will be sufficient to find the initial value of the function (1) i.e. a.

Now, putting the value x = 0 and y = \frac{1}{2} in the equation (1) we get, f(x) = a(b)^{x}

⇒ \frac{1}{2} = a(b)^{0} = a

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10 0
3 years ago
Read 2 more answers
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