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Dmitry_Shevchenko [17]
3 years ago
14

1+1=? Sana Naman yung tamang sagot lang

Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0

Answer: 2

The answer is 2. Its very simple

Naily [24]3 years ago
5 0

Answer:

2

Step-by-step explanation:

1+ 1 = 2

Hope this helps

plz mark as brainliest!!!!!!!

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Given congruent triangles ΔRST ΔLMN where MN = 33, LN = 54, and RT = 4x+6 . Find the value of x
Scilla [17]

Answer:

x=12

Step-by-step explanation:

We know that both triangles are congruent meaning corresponding parts are equal. We know that line LN=54 and that RT=LN meaning that RT also equals 54. With that information we can simply subtract 6 from 54 to get 48 then divide by 4 to get  12. Hope this helps!

7 0
3 years ago
Markel said he has 4 times
bulgar [2K]

Answer:

4:1

Step-by-step explanation:

8 0
3 years ago
Mary invests £12000 in a savings account the account pays 1.5% compound interest per year work out the value of her investment a
Ugo [173]
The formula for this is
A = P(1 + r/100)^n    where P =  initial investment, r = compound interest as  per cent, and n = number of years.

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3 0
3 years ago
Let f(x) = -3x³ + 4 and g(x) = -8x² + 2x. What is f(x) g(x)?<br> ·
SashulF [63]

Answer:

{ \tt{f(x).g(x) = ( - 3 {x}^{2}  + 4)( { - 8x }^{2} + 2x) }} \\   = { \tt{( - 3 \times  - 8) {x}^{(2 + 2)} +  (2 \times  - 3)  {x}^{(2 + 1)} + ( - 8 \times 4) {x}^{2}  + (4 \times 2)x }} \\  = { \tt{24 {x}^{4} - 6 {x}^{3} - 32 {x}^{2}    + 8x}}

7 0
2 years ago
A shipment of 20 similar laptop computers to a retail outlet contains 3 that are defective. If a school makes a random purchase
otez555 [7]

Answer:

Step-by-step explanation:

Total number of laptops, N = 20

Defective laptops, n = 3

School purchase 2 laptops

Case 1:

Both laptops are non defective

Probability to choose 2 laptops which are non defective

Number of non defective laptops = 20 - 3 = 17

Total number of laptops = 20

Probability, P = 17/20 = 0.85

Case 2:

One laptop is defective

Probability to chose 1 defective and one non defective laptop

P' = 3/20 x 17/19 = 0.134

Case 3:

Both laptops are defective

Choosing of 2 laptops out of 3 = 3 C 2 = 3

choosing of 2 laptops out of 20 = 20 C 2 = 190

Probability of choosing two defective laptops = 3 / 190 = 0.0158

P'' =

4 0
3 years ago
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