To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.
0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
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Reproduction is the function of both living <u>plants</u> and organisms.
<h3>What is reproduction?</h3>
Reproduction can be defined as a biological process through which all living organisms (parents) produce their offspring, especially through mating.
<h3>The types of reproduction</h3>
Basically, there are two (2) main types of reproduction and these include;
Generally, reproduction is one of the main characteristics of a living organism and plants.
In conclusion, reproduction is a function that is peculiar to both living <u>plants</u> and organisms.
Read more on reproduction here: brainly.com/question/2538465
Answer:
RNA contains an additional oxygen atom on the ribose sugar. (Ans. C)
Explanation:
RNA contains a sugar which is known as ribose, and which contains an extra group of hydroxyl (OH-) while DNA contains deoxyribose sugar.
RNA contains four nitrogenous bases cytosine, adenine, guanine, and uracil, while DNA contains cytosine, adenine, guanine, and thymine.
Double helix means two stranded structure like DNA, while RNA is single stranded.
DNA molecule is much longer polymer than RNA molecule.
Answer:
Answer:
Genotype Phenotype
SS 1/4 Short hair 3/4
Ss 2/4 Short hair 3/4
ss 1/4 Long hair 1/4
Explanation:
Both are heterozygous for the trait so we can expect that the cross would be:
Ss x Ss
S s
S SS Ss
s Ss ss
So the resulting off-spring would have the following genotype and phenotype:
1 out of 4 will have a genotype of SS.
2 out of 4 or half will have a genotype of Ss.
1 out of 4 will have a genotype of ss.
But because short hair is dominant the phenotype ratios would differ because Ss and SS would express short hair, so we add up their ration:
Short hair: 1/4 + 2/4 = 3/4
Long hair: 1/4
So in summary:
Genotype Phenotype
SS 1/4 Short hair 3/4
Ss 2/4 Short hair
ss 1/4 Long hair 1/4
Explanation:
