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3 years ago

Helpppppp I'll give you brainy est

Mathematics

1 answer:

blagie [28]3 years ago

3 0

Answer:

Put those equations into desmos

Step-by-step explanation:

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From the parent function LaTeX: f\left(x\right)=\frac{5}{x}f ( x ) = 5 x, write the equation of the function g(x) if f(x) is tra

madreJ [45]

Answer:

idk

Step-by-step explanation:

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4 years ago

Suppose a triangle has two sides of length 14 and 14, and that the angle between these two sides is 122 degrees. What is the len

Dafna1 [17]

Suppose we have a triangle ΔABC,

Length of AB = 14

Length of AC = 14

Angle ∠BAC = 122 degree

This triangle is isosceles triangle so, angle B = angle C = (180 - 122)/2 = 29

We know the two side and one angle of triangle ABC, here we use Sine Rule.

(In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of a triangle (any shape) to the sines of its angles.)

According to the law,

$\frac{a}{sinA} = \frac{b}{sinB} = \frac{c}{sinC}$

$\frac{a}{sinA} =\frac{14}{sin29}$

Solve for a

a = 24.49 option C

5 0

4 years ago

Read 2 more answers

PLEASE HELP!!!

frutty [35]

Answer:

1st question: C

2nd question: Increasing (the slope)

3rd question: don't understand what's being asked

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Fill in the missing numbers.<br> __+-3.5=7.25<br> -3/4-__=1/2<br> -2 3/8-(-4 2/3) = __

blondinia [14]

Answer:

10.75

-5/4

2 7/24

Step-by-step explanation:

1.)

__+-3.5=7.25

Let missing number = x

x - 3.5 = 7.25

x = 7.25 +3.5

x = 10.75

2.)

-3/4-__=1/2

Let missing number = x

-3/4 - x = 1/2

-3/4 - 1/2 = x

(-3 - 2) / 4 = x

-5/4 = x

3.)

-2 3/8-(-4 2/3) = x

-2 3/8 + 4 2/3 = x

-19/8 + 14/3 = x

(-57 + 112) / 24 = x

55 / 24 = x

2 7/24

3 0

3 years ago

7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.

blondinia [14]

$\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill$

$\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}$

7 0

2 years ago

Helpppppp I'll give you brainy est​

Helpppppp I'll give you brainy est