Question

In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC. ​

Answer 1

Answer:

By angle sum property:

BAC+ABC+BCA=180°

90°+45°+x=180°

135°+x=180°

x=45°=BCA

since BCA=ABC= 45° each

therefore,

$AB=AC \\ (isosceles \: triangle \: \\ theorem)$

Hope it helps you<3