3 years ago

In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC.

Mathematics

1 answer:

Amiraneli [1.4K]3 years ago

6 0

Answer:

<h2>By angle sum property:</h2>

BAC+ABC+BCA=180°

90°+45°+x=180°

135°+x=180°

x=45°=BCA

<h2>since BCA=ABC=<u> </u>45° each </h2><h2>therefore,</h2>

$AB=AC \\ (isosceles \: triangle \: \\ theorem)$

<h2><em><u>Hope </u></em><em><u>it </u></em><em><u>helps</u></em><em><u> you</u></em><em><u><</u></em><em><u>3</u></em></h2>

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In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC. ​

In the given figure, BAC = 90° and ABC = 45°. Prove that: AB = AC.