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3 years ago

10

Three apples and two oranges cost $3.80, while two apples and one orange costs $2.30 Find the cost of an orange.

1 answer:

zaharov [31]3 years ago

5 0

The cost of an orange would be $6.10

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Solve The Math equation below

Angelina_Jolie [31]

The Answer Is D. x=72

3 0

3 years ago

Select all figures for which there exists a direction such that all cross sections taken at that direction are congruent.

dimulka [17.4K]

Answer:

Rectangular Prism
Cube
Cylinder

Step-by-step explanation:

I know because I just did it on an assignement and it said these were the right answers.

4 0

3 years ago

Ralph and Jody go to the store to buy chips and candy bars. Ralph buys 3 bags of potato chips and 4 candy bars for 375 cents. Jo

s2008m [1.1K]

3x+4y = 375
6x+ 4y= 600
-------------------
6x-3x = 600 - 375

3x=225
x=225:3
x=75 cents

3*x+4y= 375
3*75+4y=375
225 +4y = 375
4y=375-225
4y=150
y=150:4
y=37,5 cents

the price is 75+37,5=112,5 cents for one bag of potato chips and one candy bar

3 0

3 years ago

Your neighbor has decided to enlarge his garden. The garden is rectangular with width 6 feet and length 15 feet. The new garden

Nana76 [90]

Answer:

Original garden: 42 feet

Enlarged garden: 98 feet

Step-by-step explanation:

Perimeter = length (2) + width (2)

<u>Original perimeter:</u>

P = 15(2) + 6(2)

P = 30 + 12

P = 42 feet

In this problem, similar is proportional, so the new garden will be proportional to the old one.

If the original length was 15 and the new length is 35, then 15 would have had to have been multiplied by 2 1/3. That means you need to multiply 6 by 2 1/3, which is 14. That means the dimensions of the enlarged yard is 14 (width) × 35 (length).

<u>Enlarged perimeter</u>

P = 35(2) + 14(2)

P = 70 + 28

P = 98 feet

4 0

3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago