295 times 67 long multiplication

If the dimensions of a pentagonal prism are quadrupled, then the surface area of the prism is multiplied by eight.

Answer:

false

Step-by-step explanation:

the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.

when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.

so, quadrupling the dimensions would multiply the areas by 16.

8 0

3 years ago

Scenario: A new Swimming pool is opening up this summer in the Bronx. Students that are 13 - 18 years old can use the pool, gym

MA_775_DIABLO [31]

The answer to your question is 15(12)+40=?
15 being the per month fee, 12 being all 12 months, and 40 being the sign up fee. You can also put 15x12+40=?

3 0

3 years ago

65% of the total number of students are girls and there are 224 boys. find the percent of boys ? find the number of girls?

SOVA2 [1]

ANSWER:

Well the percentage of boys would be 35%

I believe the number of girls is 416

hope this helps

7 0

3 years ago

A terrorist planted an armed nuclear bomb and your job is to disabled it . There are 4 wires to the device. You will disable the

Vesnalui [34]

1/6

Step-by-step explanation:

According to the question, the right combination of 2 wires cut (out of the 4 wires ) will defuse the bomb. To find all the possible combinations we using the following formulae;

nCr = n! / r! * (n - r)!

⁴₂C = 4! / 2! * (4-2)!

⁴₂C = 24 / 2 * 2

⁴₂C = 6

There are a possible 6 combinations

Therefore for probability of cutting the right combination of 2 wires is 1/6

Learn More:

To learn more about combinations check out;

brainly.com/question/3374511

brainly.com/question/3901018

#LearnWithBrainly

3 0

3 years ago

Suppose a poll is taken that shows that 765 out of 1500 randomly selected, independent people believe the rich should pay more

Zanzabum

Answer:

$z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775$

$p_v =P(z>0.775)=0.219$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

Step-by-step explanation:

Data given and notation

n=1500 represent the random sample taken

X=765 represent the successes

$\hat p=\frac{765}{1500}=0.51$ estimated proportion of successes

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:

Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>0.775)=0.219$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

8 0

3 years ago