Answer:
Step-by-step explanation:
Given
- 3 rectangular cards
- each card is 8 inches by 9 inches
The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:
Put 3 cards together according to the length
So the smallest possible perimeter is:
8 + 8 + 8 + 8 + 8 + 8 + 9 + 9 = 66 inches as you can see in the attached photo.
The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.
Hope it can find you well.
-320. The negative sign represents loss. In all of the other cases, values are either being added or not changed at all.
1 : the perimeter of a circle The circle measures 22 inches in circumference. 2 : the external boundary or surface of a figure or object : periphery from the center to the circumference of the sphere.
A.) Since there are no restrictions as to the dimensions of the candle except that their volumes must equal 1 cubic foot and that each must be a cylinder, we have the freedom to decide the candles' dimensions.
I decided to have the candles equal in volume. So, 1 cubic foot divided by 8 gives us 0.125 cubic foot, 216 in cubic inches.
With each candle having a volume of 216 cubic inches, I assign a radius to each: 0.5 in, 1.0 in, 1.5 in, 2.0 in, 2.5 in, 3.0 in, 3.5 in, and 4.0 in. Then, using the formula of the volume of a cylinder, which is:
V=pi(r^2)(h)
we then solve the corresponding height per candle. Let us let the value of pi be 3.14.
Hence, we will have the following heights (expressed to the nearest hundredths) for each of the radius: for
r=2.5 in: h=11.01 in
r=3.0 in: h= 7.64 in
r=3.5 in: h= 5.62 in
r=4.0 in: h= 4.30 in
r=4.5 in: h= 3.40 in
r=5.0 in: h= 2.75 in
r=5.5 in: h= 2.27 in
r=6.0 in: h= 1.91 in
b. each candle should sell for $15.00 each
($20+$100)/8=$15.00
c. yes, because the candles are priced according to the volume of wax used to make them, which in this case, is just the same for all sizes
Answer:
Step-by-step explanation:
hello : note 297 no 279
297 =3×99
99 = 3 ×33
33=3×11
this the geometric sequence. ( comon : 3)
the nth term is : An = A1 × r^n when : r = 3 and A1 =11
if n = 19 A19 = 11×3^19
