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gavmur [86]
3 years ago
9

The density of a certain material is such that it weighs 5 ounces per fluid ounce of volume. Express this density in pounds per

liter
Mathematics
1 answer:
pav-90 [236]3 years ago
3 0

Answer:

Don't lisen to that the anwer is 0.3125

Step-by-step explanation:

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The Pythagorean theorem is a² + b² = c². Solve for b. b=±c+a−−−−√ b=±c2−a2−−−−−−√ b=±c2+a2−−−−−−√ b=±c−a−−−−√
uysha [10]

a^{2} +b^{2} =c^{2}

As we have to solve for b, it means we have to isolate b

So first of all subtract a^{2} from both sides

So we get

b^{2} =c^{2} -a^{2}

Now we need b , but its b^2 , so we can take square root on both sides.


taking square roots on both sides

b= +- \sqrt{c^2 -a^2}


Hence option B is correct

4 0
3 years ago
What value is true of x makes this equation true 0.7x-5=0.2x+1
Sever21 [200]

Answer:

x=12

Step-by-step explanation:

First you make sure x is on both sides of the equation. So you do 0.7x-5-0.2x=0.2x+1-0.2x. Which just simplifies to 0.5x-5=1. You make sure x is the only thing on that side of the equation so you do 0.5x-5+5=1+5 which simplifies to 0.5x=6. Multiply the equation times 2 to just have x. x=12. The value that makes true of x is 12.

7 0
3 years ago
Points E, F, and D are located on circle C. Circle C is shown. Line segments E C and D F are radii. Lines are drawn from points
elena55 [62]

Answer:

Option (1). 34°

Step-by-step explanation:

From the figure attached, CE and CD are the radii of the circle C.

Central angle CED formed by the intercepted arc DE = 68°

Since measure of an arc = central angle formed by the intercepted arc

Therefore, m∠CED = 68°

Since m∠EFD = \frac{1}{2}(m\angle ECD) [Central angle of an intercepted arc measure  the double of the inscribed angle by the same arc]

Therefore, m∠EFD = \frac{1}{2}(68)

                               = 34°

Therefore, Option (1) 34° will be the answer.

7 0
3 years ago
Read 2 more answers
Evaluate [(40 + 5) − 32] ÷ 9 ⋅ 2.
CaHeK987 [17]
(45 - 32) / 9 * 2
13 / 18

the. answer is 13 / 18
3 0
3 years ago
Read 2 more answers
Last year Baron Enterprises had $800 million of sales, and it had $270 million of fixed assets that were used at 65% of capacity
Svetllana [295]

Answer: B. $430.80

Step-by-step explanation:

Given : Last year Baron Enterprises had $800 million of sales.

It had $270 million of fixed assets that were used at 65% (=0.65) of capacity last year.

Now, the used asset = 0.65\times270=\$175.5million

Now, Baron Enterprises had $800 million of sales in $175.5 million of assets , if we use all of $270 million of fixed assets , then the sales will be :-

\dfrac{800}{175.5}\times270=1230.76923077\approx1230.80\text{ million}

Now, the increase in Baron's sales before it is required to increase its fixed assets = \$1230.80-$800=\$430.80\text{ millions}

Hence, the increase in Baron's ( in million ) sales before it is required to increase its fixed assets = $430.80

8 0
3 years ago
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