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ad-work [718]
3 years ago
8

HELPPPO !% PT PLZZZZZZZZZZZZZZZZZZZZZ

Mathematics
1 answer:
kramer3 years ago
5 0

Answer:

6/12,  2/4,

Step-by-step explanation:

6/12 because half of 12 is 6.

2/4 because half of 4 is 2.

Both can equal 1/2.

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Find the length of the unknown side. Round your answer to the nearest whole number.
aleksley [76]
The answer is 72.8. in order to solve this problem, you need to use the pythagorean theorem. the equation is c^2-b^2=a^2.

75^2-18^2=a^2

75 squared minutes 18 squared is 5301. then you need to find the square root of 5301.

the square root of 5301 is 72.8079666, rounding to 72.8.
6 0
3 years ago
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Select steps that could be used to solve the equation 1 + 3x = -x + 4.
Tema [17]

For this case we have the following equation:

1 + 3x = -x + 4

We must solve the equation by following the steps below:

We subtract 1 from both sides of the equation:

3x = -x + 4-1

On the right side of the equation we have that different signs are subtracted and the sign of the major is placed:

3x = -x + 3

We add x to both sides of the equation:

3x + x = 3\\4x = 3

We divide between 4 on both sides of the equation:

x = \frac {3} {4}

Thus, the correct option is option B

Answer:

x = \frac {3} {4}

Option B

6 0
4 years ago
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Write 72,300,000 in scientific notation
e-lub [12.9K]

72.3x10^{6}
7 0
3 years ago
the present ages of two brothers are 15 years and 22 years respectively after how many years will the product of their ages be 4
svetoff [14.1K]
Let (15+x) and (22+x) be the future ages of the brothers


15+x+22+x= 408

Collect like terms

37+2x=408

Move 37 to the other side as a negative number


2x=371

Divide both sides by 2


371/2 is 185.5

So, after 185.5 years, their ages will add up to be 408

4 0
3 years ago
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<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E%7B2%7D%20%2B4x%2B4" id="TexFormula1" title="\sqrt{x^{2} +4x+4" alt="\sqrt{x^{2}
Anna35 [415]

Answer:

Given,

\sqrt{ {x}^{2}  + 4x + 4}  - 3 = 0 \\  =  >  \sqrt{ {x}^{2}  + 4x + 4}  = 3 \\  =  >  {( \sqrt{ {x}^{2}  + 4x + 4} })^{2}  =  {3}^{2}  \\  =  >  {x}^{2}  + 4x + 4 = 9 \\  =  >  {x}^{2}  + 4x + 4 - 9 = 0 \\  =  >  {x}^{2}  + 4x - 5 = 0 \\  =  >  {x}^{2}  + 5x - x  - 5 = 0 \\  =  >  x(x + 5) - 1(x  + 5) = 0 \\  =  > (x - 1)(x  + 5) = 0 \\  \\  \sf \: either \: x - 1 = 0 \:  \:  \:  \:  \\  =  > x = 1 \:  \:  \\  \\  \sf \: or \\ x + 5 = 0 \\  =  > x =  - 5 \\  \\ \green{ \boxed{  \bf \:  \:  \:  \: \: x = 1 \:  \: or \:  - 5}}

But if we put the value of x = 5 then it doesn’t satisfy the equation.

So,

X = 1

5 0
3 years ago
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