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kolbaska11 [484]
3 years ago
10

Please help me ineed it now ​

Mathematics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

look at explanation

Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. \frac{180 km}{4 hrs} (divide by 4 to get unit rate)

     unit rate = \frac{45km}{1hr}

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know \frac{40 miles}{1 hr}, the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is \frac{40 miles}{1 hr}. "

3. Knowing that the constant speed of the plane is \frac{800 km}{1 hour\\}, we can scale then add half of the unit rate to get our answer.

\frac{800 km}{1 hour\\} x 3 = \frac{2400 km}{3 hrs}   800 x 3 = 2400

then add half of unit rate which is \frac{400 km}{30 mins}  \sqrt[2]{800} = 400

so, our answer is \frac{2800 km}{3.5 hours}

4.  \frac{3km}{30 mins} <--- ( divided by 2) \frac{6 km}{1 hr} ( multiplied x 2.5) ---> \frac{15 km}{2.5 hrs}

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

5. The boys speed is \frac{4 km}{1 hr}. All we need to do is divide by 2. \sqrt[2]{8} = 4

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all right triangles are 90 degrees and in total there is 9x so you divide 90 by 9 to get x=10 A

6 0
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PLEASE HELP I WILL GIVE BRAINLYEST
insens350 [35]

∠13 = 70.5° [Vertically Opposite angles]

∠13+∠14=180° [Linear pair]

70.5°+∠14=180°

∠14=180-70.5

∠14=109.5

∠15=∠14=109.5 [Vertically opposite angles]

∠13=∠12= 70.5° [Co-interior angles]

∠12=∠10= 70.5° [Vertically Opposite angles]

∠14=∠11=109.5 [Co-interior angles]

∠9=∠11= 109.5 [Vertically opposite angles]

∠13=∠7= 70.5° [Alternate interior angles]

∠7=∠5=70.5° [Vertically Opposite angles]

∠7+∠8=180° [Linear Pair]

70.5+∠8=180

∠8=180-70.5

∠8=109.5°

∠8=∠6= 109.5° [Vertically Opposite angles]

∠6=∠3=109.5° [Co-interior angles]

∠7=∠2=70.5° [Co-exterior angles]

∠2=∠4= 70.5° [Vertically Opposite angles]

∠3=∠1= 109.5° [Vertically Opposite angles]

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3>Measures of all angles in sequence⤵️</h3>

  • ∠1= 109.5°
  • ∠2= 70.5°
  • ∠3= 109.5°
  • ∠4= 70.5°
  • ∠5= 70.5°
  • ∠6= 109.5°
  • ∠7= 70.5°
  • ∠8= 109.5°
  • ∠9= 109.5°
  • ∠10= 109.5°
  • ∠11= 70.5°
  • ∠12= 109.5°
  • ∠13= 70.5°
  • ∠14= 109.5°
  • ∠15= 109.5°
  • ∠16= 70.5°
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