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3 years ago

Find the value of x rounded to the nearest tenth

Mathematics

2 answers:

just olya [345]3 years ago

7 0

Answer: The correct option is (C) 12.5 units.

Step-by-step explanation: We are given to find the value of x rounded to the nearest tenth.

From the figure, we see a right-angled triangle with one acute angle measuring 28°.

With respect to the angle with measure 28°, the length of the base is 11 units and the length of the hypotenuse is x units.

So, from trigonometric ratios, we have

$\cos28^\circ=\dfrac{11}{x}\\\\\\\Rightarrow 0.8829=\dfrac{11}{x}\\\\\\\Rightarrow x=\dfrac{11}{0.8829}\\\\\Rightarrow x=12.4589.$

Rounding to nearest tenth, we get

x = 12.5 units.

Thus, the required value of x is 12.5 units.

Option (C) is CORRECT.

elena-14-01-66 [18.8K]3 years ago

5 0

Cos28=11/x
x=11/cos28
it will be c

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(-3,600,000,000)x(0.00000824)

Nadusha1986 [10]

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3 years ago

Find an equation of the line through the given point and perpendicular to the given line

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

For two lines to be perpendicular, the slope of one line is the negative reciprocal of the other line. The equation of the given line is

y = 2x - 2

Comparing with the slope intercept form,

Slope, m = 2

This means that the slope of the line that is perpendicular to it is -1/2

The given points are (-3, 5)

To determine c,

We will substitute m = -1/2, y = 5 and x = - 3 into the equation, y = mx + c

It becomes

5 = -1/2 × - 3 + c

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c = 5 + 3/2

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y = -x/2 + 13/2

4 0

3 years ago

Can you find the mean for these two questions:

Molodets [167]

1) Mean Absolute Deviation = 1.75

2) Mean = 244

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4 years ago

Read 2 more answers

A sample of 4 different calculators is randomly selected from a group containing 18 that are defective and 35 that have no defec

Sphinxa [80]

<span>1.

P(</span>at least one of the calculators is defective)=

1- P(none of the selected calculators is defective).

2.

P(none of the selected calculators is defective)

=n(ways of selecting 4 non-defective calculators)/n(total selections of 4)

3.

selecting 4 non-defective calculators can be done in C(35, 4) many ways,

where $C(35, 4)= \frac{35!}{4!31!}= \frac{35*34*33*32*31!}{4!*31!}= \frac{35*34*33*32}{4!}= \frac{35*34*33*32}{4*3*2*1}= 52,360$

while, the total number selections of 4 out of 18+35=53 calculators can be done in C(53, 4) many ways,

$C(53, 4)= \frac{53!}{4!*49!}= \frac{53*52*51*50}{4*3*2*1}= 292,825$

4. so, P(none of the selected calculators is defective)= $\frac{52,360}{292,825} =0.18$

5. P(at least one of the calculators is defective)=

1- P(none of the selected calculators is defective)=1-0.18=0.82

Answer:0.82

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4 years ago

the end point of a line segment are (13,-15) and (m,-9) what is the value of m if the midpoint of the line segment is (10,-12).

grandymaker [24]

Answer:

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3 years ago