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Leviafan [203]
3 years ago
14

IF YOUR VEHICLE BREAKS DOWN, YOU SHOULD?

Engineering
1 answer:
KatRina [158]3 years ago
7 0

Answer:

1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS

Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).

2. SLOW DOWN AND PULL OFF THE ROAD

Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.

3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE

The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.

4. STAY IN YOUR VEHICLE

If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.

5. BE VISIBLE

Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.

6. SET UP FLARES OR TRIANGLES

Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.

7. CALL FOR HELP

Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.

Hope this helps :)

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1. A wood board is one of a dozen different parts in a homemade robot kit. The width, depth, and height dimensions of the board
otez555 [7]

Answer:

183.75 cubic inches.

Explanation:

The volume of the wood board is determine by means of this expression:

V = w \cdot h \cdot l

By replacing variables:

V = (7.5 in) \cdot (14 in) \cdot (1.75 in)\\V = 183.75 in^{3}

3 0
3 years ago
A helicopter moves horizontally in the x direction at a speed of 120 mi/h. Knowing that the main blades rotate clockwise when vi
devlian [24]

Answer:

The instantaneous axis of rotation=

x = 0 ; z = 8.4 ft

Explanation:

Given:

Speed of helicopter, Vo= 120 mi/h, converting to ft/sec, we have:

\frac{5280 * 120}{60*60}

= 176 ft/s

Angular velociyy, w = 220 rpm, converting to rad/sec, we have: \frac{200*2*pi}{60} =20.95 rad/s

The helicopter moves horizontally in the x direction at a speed of 120 mi/h, this means that the helicopter moves in the positive x direction at 120mi/h

To find the instantaneous axis of rotation of the main blades, we have:

Where Vc = 20.95 rad/s

Vo = 176 ft/s

z = \frac{V_0}{V_c} = \frac{176ft/s}{20.95rad/s}

= 8.4 ft

Therefore the axis of rotation=

x = 0 ; z = 8.4 ft

4 0
3 years ago
A company, studying the relation between job satisfaction and length of service of employees, classified employees into three le
Wewaii [24]

Answer:

Below see details

Explanation:

A) It is attached. Please see the picture

B) First to calculate the overall mean,  

μ=65∗25/75+80∗25/75+95∗25/75  

μ=65∗25/75+80∗25/75+95∗25/75 = 80

Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634

And E(MSE) = σ^2= 9

C) Yes, it is substantially large than E(MSE) in this case.

D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.

3 0
3 years ago
A square steel bar has a length of 7.2 ft and a 2.5 in by 2.5 in cross section and is subjected to axial tension. The final leng
Nataly_w [17]

Answer:

A) ν = 0.292

B) ν = 0.381

Explanation:

Poisson's ratio = - (Strain in the direction of the load)/(strain in the direction at right angle to the load)

In axial tension, the direction of the load is in the length's direction and the direction at right angle to the load is the side length

Strain = change in length/original length = (Δy)/y or (Δx)/x or (ΔL/L)

A) Strain in the direction of the load = (2.49946 - 2.5)/2.5 = - 0.000216

Strain in the direction at right angle to the load = (7.20532 - 7.2)/7.2 = 0.0007389

Poisson's ratio = - (-0.000216)/(0.0007389) = 0.292

B) Strain in the direction of the load = (2.09929 - 2.1)/2.1 = - 0.0003381

Strain in the direction at right angle to the load = (5.30470 - 5.3)/5.3 = 0.0008868

Poisson's ratio = - (-0.0003381)/(0.0008868) = 0.381

7 0
3 years ago
Plz answer all of these questions!
statuscvo [17]

Answer: all you need to to is go to help me with this question.cm

Explanation:

5 0
3 years ago
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