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timama [110]
3 years ago
14

A company, studying the relation between job satisfaction and length of service of employees, classified employees into three le

ngth-of-service groups (less than 5 years, 5-10 years, more than 10 years). Suppose µ1 = 65, µ2 = 80, µ3 = 95, and σ= 3, and that ANOVA model Yij=μi+ϵij is applicable.
a. Draw a representation of this model
b. Find E(MSTR) and E(MSE) if 25 employees from each group are selected at random for intensive interviewing about job satisfaction.
c. Is E(MSTR) substantially large than E(MSE) here?

Engineering
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

Below see details

Explanation:

A) It is attached. Please see the picture

B) First to calculate the overall mean,  

μ=65∗25/75+80∗25/75+95∗25/75  

μ=65∗25/75+80∗25/75+95∗25/75 = 80

Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634

And E(MSE) = σ^2= 9

C) Yes, it is substantially large than E(MSE) in this case.

D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.

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Answer:

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Explanation:

Given;

Case1 :

height of vertical surface, L = 1 m

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Case 2:

height of vertical surface, L = 0.6 m

width of vertical surface, w = 1 m

At an assumed film temperature of air = 300 K

then, read off from heat transfer table, temperature inverse β, surface area flow rate v, and Pr, to determine Rayleigh number for the two cases.

β = 1/300 = 0.00333 K⁻¹

v = 15.89 x 10⁻⁶ m²/s

Pr = 0.69

Case 1, L = 1 m

R_a = \frac{g\beta TL^3P_r}{v^2}

R_a = \frac{9.8*0.00333* 20*1^3*0.69}{(15.89x10^{-6})2} \\\\R_a = 1.784 *10^9

Case 2, L = 0.6 m

R_a = \frac{g\beta TL^3P_r}{v^2} \\\\R_a = \frac{9.8*0.00333* 20*0.6^3*0.69}{(15.89*10^{-6})^2}\\\\ R_a = 3.853 *10^8

From the values of Rayleigh numbers above, case 1 is Turbulent flow while case 2 is laminar flow

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Ratio of heat transfer rate is given as:

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3 years ago
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4 0
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Create a class called Candle to represent a candle. It should have four private instance variables: An int for the height, an in
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5 0
4 years ago
If a torque of M = 300 N⋅m is applied to the flywheel, determine the force that must be developed in the hydraulic cylinder CD t
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Answer:

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The torque on the flywheel = 300 N-m

The force from the hydraulic cylinder will generate a moment on CA about point A.

The part of this moment that will be at point B about A must be proportional to the torque on the cylinder which is 300 N-m

we know that moment = F x d

where F is the force, and

d is the perpendicular distance from the turning point = 1 m

Equating, we have

300 = F x 1

F = 300 N   this is the frictional force that stops the flywheel

From F = μN

where F is the frictional force

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substituting, we have

300 = 0.4 x N

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3 years ago
If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ p ^ is approximately a normal distribution.
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It is true that the sampling distribution of the proportions is approximately a normal distribution.

Explanation:

Solution

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N = 50

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p ^= 0.0566

Therefore,we conclude that the sampling distribution of the proportions is approximately a normal distribution.

4 0
3 years ago
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