The pressure drop of air in the bed is 14.5 kPa.
<u>Explanation:</u>
To calculate Re:

From the tables air property

Ideal gas law is used to calculate the density:
ρ = 
ρ = 1.97 Kg / 
ρ = 
R =
= 8.2 ×
/ 28.97×
R = 2.83 ×
atm / K Kg
q is expressed in the unit m/s
q = 1.24 m/s
Re =
Re = 2278
The Ergun equation is used when Re > 10,


= 4089.748 Pa/m
ΔP = 4089.748 × 3.66
ΔP = 14.5 kPa
Answer:
Amperes WB =<em> </em>
Explanation:
Amperes will flow back to the negative terminal because both the positive terminal and negative terminal contain the equivalent amount of current that will flow and it works in the starter motor.
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Answer:
86701 Micrometers.
Explanation:
Multiply 0.86701 dm by 100,000 to get 86701 um.