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3 years ago

Answer this for me please!

Mathematics

1 answer:

kvv77 [185]3 years ago

6 0

Answer:

i Don't know.

Step-by-step explanation:

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What is the expression 6 times the quantity n plus 7? (there is no picture for it)

lesantik [10]

Answer:

it's 6n + 7

Step-by-step explanation:

hope this helped a little bit :))

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3 years ago

Read 2 more answers

The cost of 8 adults tickets to a movie is $66. What is the cost of one adult ticket?

Papessa [141]

If you want to find the cost per adult if 8 of them buy tickets for a total of $66, you would divide the total cost by the number of tickets bought. So, $66 divided by 8 would equal to $8.25 per ticket.

6 0

4 years ago

Giving brainliest Find the area of the composite figure below.

musickatia [10]

810 because multiplying it all adds up to 810

5 0

3 years ago

TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) $n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51$

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation

n=2341 represent the random sample taken

X represent the people that they have watched digitally streamed TV programming on some type of device

$\hat p=0.55$ estimated proportion of people that they have watched digitally streamed TV programming on some type of device

$\alpha=0.01$ represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}}$

Part a) Confidence interval

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.