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3 years ago

What is a difference of squares with a factor of (3x + 7) ?

Mathematics

1 answer:

Inga [223]3 years ago

7 0

Answer:

9x² - 49

Step-by-step explanation:

A difference of squares factors in general as

a² - b² = (a + b)(a - b)

Given (3x + 7) with a = 3x and b = 7

Then the other factor is (3x - 7)

(3x + 7)(3x - 7)

= (3x)² - 7²

= 9x² - 49

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3 years ago

On Friday ,537 people attended a play.for Saturdays matinee there were 812 people.about how many more people attended the play o

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3 years ago

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Rom4ik [11]

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4 years ago

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Y is inversely proportional to x

irinina [24]

A ) equation would be X = Z / Y
B ) if X = 9 ------------> Y = 1/7
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3 years ago

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Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin

icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

$\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}$

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

$y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}$

$y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}$

$y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}$

It is linear differential equation because this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

$y'+P(x)y=g(x)$

$P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}$

$\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}$

Homogeneous equation

$\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}$

Degree of f and g are same.

$f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x$

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0

3 years ago