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svetoff [14.1K]
2 years ago
6

What is a difference of squares with a factor of (3x + 7) ?

Mathematics
1 answer:
Inga [223]2 years ago
7 0

Answer:

9x² - 49

Step-by-step explanation:

A difference of squares factors in general as

a² - b² = (a + b)(a - b)

Given (3x + 7) with a = 3x and b = 7

Then the other factor is (3x - 7)

(3x + 7)(3x - 7)

= (3x)² - 7²

= 9x² - 49

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Answer:

Given : ∠ABC is a right angle, ∠D BC is a straight angle.

To prove :∠AB D is a right angle.

Proof: ∠ ABC = 90°[ Given]

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now, ∠ AB D and ∠ AB C are adjacent angles forming linear pair.

∠ AB D +∠ AB C =180° [By linear pair axiom]

⇒∠ AB D + 90= 180°

⇒∠ AB D=180°-90°

⇒∠ AB D=90°

∠AB D is a right angle

Hence proved.




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