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TEA [102]
3 years ago
5

Given the function f(x) = -5+4x, then what is -f(x) as a simplified polynomial?

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
4 0

Answestf u

Step-by-step explanatio

ggggggggggggggggggggggggggggggggggg

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The following shapes are similar. JK:ST is 2:1 and the length of JN is 6/2. What is the length of SW?
Anastasy [175]

Answer:

first, that last tab lol. and its 3/4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
It is claimed that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%. A
attashe74 [19]

Answer:

Conclusion is that there is sufficient evidence to reject the claim that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%.

Step-by-step explanation:

We are given;

Population proportion; p = 60% = 0.6

Sample mean: x¯ = 315

Sample size; n = 500

Significance level = 0.09

Defining the hypothesis, we have;

Null Hypothesis; H0: p = 0.6

Alternative hypothesis; Ha: p > 0.6

z-score formula in this case is;

z = (x¯ - np)/√(np(1 - p))

Plugging in the relevant values;

z = (315 - (500 × 0.6))/√(500 × 0.6(1 - 0.6))

z = 1.72

From z-distribution table, the p-value at z = 1.72 is;

1 - P(Z ≤ z-score)

This gives:

p-value = 1 - 0.95728 = 0.04272

Thus p-value is less than the significance level of 0.09, thus we will reject the null hypothesis and conclude that there is sufficient evidence to reject the claim that the proportion of people who favor the use of oxygenated fuels year around to reduce air pollution is 60%.

6 0
3 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
What percent of 110 is 88
jonny [76]

Answer:

80 percent

Step-by-step explanation:

What percent of 110 is 88

p * 110 = 88

divide by 110 on each side

p = 88/110

p = .8

multiply by 100 to get percent

80 percent

5 0
3 years ago
Read 2 more answers
A suspension bridge with weight uniformly distributed along its length has twin towers that extend 70 meters above the road surf
goblinko [34]

Answer:

  17.5 m

Step-by-step explanation:

The height of a parabola above its vertex is proportional to the square of the distance from the vertex.

<h3>Cable height</h3>

The towers are 1200 m apart, so each is 600 m from center. The location of interest is 300 m from center, so 1/2 the distance to a tower. Since the height is proportional to the square of the distance, the height half-way to the tower will be (1/2)² = 1/4 the height of the tower.

  (1/2)²×(70 m) = 17.5 m

The height of the cable 300 m from center will be 17.5 meters.

7 0
2 years ago
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