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Dovator [93]
4 years ago
10

Using 25 micromoles, pmoles, of CO2 consumed how many grams of glucose (MW = 180 g/mole) were produced?

Chemistry
1 answer:
Sladkaya [172]4 years ago
8 0

Grams of glucose = 0.7488 mg=748.8 μg

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

6CO₂+6H₂O⇒C₆H₁₂O₆+6O₂

25 micromoles, μmoles, of CO₂ :

moles CO₂ : moles glucose - C₆H₁₂O₆ = 6 : 1, so :

\tt moles~glucose=\dfrac{1}{6}\times 25\mu~moles=4.16\mu~moles=4.16\times 10^{-6}~moles

mass of glucose

\tt mass=mol\times MW\\\\mass=4.16\times 10^{-6}\times 180\\\\mass=7.488\times 10^{-4}g=0.7488~mg=748.8\mu g

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<h3>What is conservation of mass?</h3>

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6 0
2 years ago
A 200.-milliliter sample of CO2(g) is placed in a sealed, rigid cylinder with a movable piston at 296 K and 101.3 kPa. Determine
bagirrra123 [75]

Answer:

The final volume of the sample of gas V_{2} = 0.000151 m^{3}

Explanation:

Initial volume V_{1} = 200 ml = 0.0002 m^{3}

Initial temperature T_{1} = 296 K

Initial pressure P_{1} = 101.3 K pa

Final temperature T_{2} = 336 K

Final pressure P_{2} =  K pa

Relation between P , V & T is given by

P_{1} \frac{V_{1} }{T_{1} } = P_{2} \frac{V_{2} }{T_{2} }

Put all the values in the above equation we get

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4 0
4 years ago
Calculate the enthalpy change, ∆H in kJ, for the reaction H2O(s) → H2(g) + 1/2O2(g). Use the following information: : +279.9 kJ
Delvig [45]

Answer:

+ 291.9 kJ

Solution:

The equation given is as;

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = ?

First, as we know the heat of formation of H₂O ₍l₎ is,

H₂ ₍g₎ + 1/2 O₂ ₍g₎ → H₂O ₍l₎ ΔH = - 285.9 kJ

Now, reversing the equation will reverse the sign of heat as,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

Also, we know that,

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

Now, adding last two equations,

H₂O ₍l₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 285.9 kJ

H₂O ₍s₎ → H₂O ₍l) ΔH = + 6.0 kJ

-----------------------------------------------------------------------------

H₂O ₍s₎ → H₂ ₍g₎ + 1/2 O₂ ₍g₎ ΔH = + 291.9 kJ

4 0
3 years ago
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