We need to first add both of the solution volumes together 35+115=150. Now we can divide the volume of the ethanol by the total volume 35/150=.233. To double check we can multiply the total volume by the percentage of ethanol by volume we got as a solution 150x.233=35. So the percentage by volume of ethanol in the solution is .233x100=23.3%.
It is advisable not to wash the thermometer and hot water because it made cause the thermometer to break and mercury to leak out from it... it can also damage the accuracy of the thermometer
The molar concentration of the nitric acid solution was 0.6666 mol/L.
<em>Balanced equation</em>: KOH + HNO_3 → KNO_3 + H_2O
<em>Moles of KOH</em>: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)
= 33.33 mmol KOH
<em>Moles of HNO_3</em>: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)
= 33.33 mmol HNO_3
<em>Concentration of KOH</em>: <em>c </em>= "moles"/"litres" = 33.33 mmol/50.00 mL
= 0.6666 mol/L
<span>Deep geological disposal is widely agreed to be the best solution for final disposal of the most radioactive waste produced.
</span>Geological disposal<span> involves isolating radioactive waste </span>deep<span> inside a suitable rock volume to ensure that no harmful quantities of radioactivity ever reach the surface environment.
</span>
Hope this helps :)
