ANSWER
Yes it is very true
<u>EXPLANATION</u>
If the two equations intersect at then this point must satisfy the two equations.
We substitute in to erquation (1)
We now substitute in to erquation (2) also
Since the point satisfy all the two equations, it is true that they intersect at
Answer:
(a) The value of <em>x</em> is 0.30.
(b) The probability that a reported case of rabies is not a raccoon is 0.45.
(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.
Step-by-step explanation:
Denote the events as follows:
<em>R</em> = reported case of rabies is a raccoon
<em>F</em> = reported case of rabies is a fox
<em>B</em> = reported case of rabies is a bat
<em>O</em> = reported case of rabies is a some other animal.
The data provided is:
P (R) = 0.55
P (F) = 0.11
P (B) = 0.04
P (O) = <em>x</em>.
(a)
A property of a probability distribution is that the sum of all individual properties is 1.
That is,
Compute the value of <em>x</em> as follows:
Thus, the value of <em>x</em> is 0.30.
(b)
The probability of the complement of an event is the probability of its not happening.
Compute the probability that a reported case of rabies is not a raccoon as follows:
Thus, the probability that a reported case of rabies is not a raccoon is 0.45.
(c)
Compute the probability that a reported case of rabies is either a bat or a fox as follows:
Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.