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3 years ago

8

2sin^2x= sin^2x+sinxcosx/cotx

1 answer:

vekshin13 years ago

8 0

cot(<em>x</em>) = cos(<em>x</em>) / sin(<em>x</em>)

so

cos(<em>x</em>) / cot(<em>x</em>) = 1 / (1/sin(<em>x</em>)) = sin(<em>x</em>)

Then

sin²(<em>x</em>) + sin(<em>x</em>) cos(<em>x</em>) / cot(<em>x</em>) = sin²(<em>x</em>) + sin²(<em>x</em>) = 2 sin²(<em>x</em>)

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