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Westkost [7]
3 years ago
8

2sin^2x= sin^2x+sinxcosx/cotx

Mathematics
1 answer:
vekshin13 years ago
8 0

cot(<em>x</em>) = cos(<em>x</em>) / sin(<em>x</em>)

so

cos(<em>x</em>) / cot(<em>x</em>) = 1 / (1/sin(<em>x</em>)) = sin(<em>x</em>)

Then

sin²(<em>x</em>) + sin(<em>x</em>) cos(<em>x</em>) / cot(<em>x</em>) = sin²(<em>x</em>) + sin²(<em>x</em>) = 2 sin²(<em>x</em>)

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Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

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