2sin^2x= sin^2x+sinxcosx/cotx

Mathematics

1 answer:

vekshin13 years ago

8 0

cot(x) = cos(x) / sin(x)

cos(x) / cot(x) = 1 / (1/sin(x)) = sin(x)

Then

sin²(x) + sin(x) cos(x) / cot(x) = sin²(x) + sin²(x) = 2 sin²(x)

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