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2 years ago

What is (3*7) divided by 5

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

8 0

Answer:

The answer is 4.2,

Hope that helped. x

Step-by-step explanation:

3 x 7 (3*7) = 21

21 divided by 5 = 4.2.

Gnesinka [82]2 years ago

6 0

Answer:

4.2

Step-by-step explanation:

Using PEMDAS,

Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

We know that to solve (3*7) divided by 5, we will need to solve what is in the parenthesis.

So, we need to figure out what is 7*3, which is 21.

This is what we have right now:

21 divided by 5

The next step is dividing,

We divide 21 by 5 to get 4
Multiply the quotient digit (4) by the divisor 5
Subtract 20 from 21
Add a decimal place and a zero to the dividend, bring down the zero from the dividend
Divided 10 by 5 to get 2
Multiply the quotient digit (2) by the divisor 5
Subtract 10 from 10
The solution for the division is 4.2

In the end, the answer is 4.2, hope this helped!

You might be interested in

What is the value of the expression 10-1/2^4x48

kumpel [21]

Answer:

Step-by-step explanation:

3 0

3 years ago

1.dilate by 3/5 : (20,10)

inysia [295]

Answer:

a) )12,6)

b) (12,2)

c) (4,-7)

d) (9,-7)

Step-by-step explanation:

a) Dilation

When we dilate, we multiply the given scale factor by each of the coordinates

We have this as follows;

(20 * 3/5, 10 * 3/5) = (12, 6)

2. Here, we will add 5 to the x-axis value and subtract 6 from the y-axis value

We have this as;

(7+ 5, 8-6) = (12,2)

3. By reflecting across the x-axis

we have (x,y) changing to (x,-y)

so we have ;

(4,7) becomes (4,-7)

4. Rotation by 270 degrees (7,9)

If clockwise;

(x,y) becomes (y,-x)

so we have

(7,9) becoming (9,-7)

4 0

3 years ago

This is a pre calculus question that I need help with, serious answer PLEASE and thank you! Will give brainliest.

IRISSAK [1]

The wording of this question is a bit confusing... You can't write a sequence in sigma notation, but rather a series or sum. I think the question is asking you to write the sum of the sequence,

$\dfrac12,\dfrac14,\dfrac18,\ldots,\dfrac1{64}$

which would be

$\dfrac12+\dfrac14+\dfrac18+\cdots+\dfrac1{64}$

in sigma notation.

To do this, notice that the denominator in each term is a power of 2, starting with $2^1=2$ and ending with $2^6=64$ . So in sigma notation, this series is