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wolverine [178]
3 years ago
7

there are 37 chairs and 9 tables in a class room Mrs Kensington wants to put an equal number of chairs at each table how many ch

airs can she out at each table will there be any chairs left over
Mathematics
2 answers:
Veronika [31]3 years ago
6 0

Answer: 4 chairs at each table one chair leftover

Step-by-step explanation:

37 / 9 = 4.1 r

BartSMP [9]3 years ago
4 0

Answer:

4 chairs at each table and 1 leftover

Step-by-step explanation:

9 goes into 37 four times and there is a remainder of one (37-36 = 1).

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8x5=40
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How does an indirect proof different from a regular proof
prisoha [69]

Answer:

Regular proof is a method of proving the statement directly. In this method, we just proved it by using direct formula or theorem. whereas, Indirect proof is a way of proving by contradiction

Step-by-step explanation:

5 0
3 years ago
You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the
Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of .

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is \pi = 0.5

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}

0.001\sqrt{n} = 2.327*0.5

\sqrt{n} = \frac{2.327*0.5}{0.001}

(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}

n = 1353732.25

Rounding up

A sample size of at least 1,353,733 is required.

5 0
3 years ago
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