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Airida [17]
3 years ago
6

Helppp. please. thanks.​

Mathematics
2 answers:
klio [65]3 years ago
5 0
I think it might be D
Alex3 years ago
3 0

Answer : I think it might be D

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Write the equation of the line in slope intercept form​
Neko [114]

Answer:

y= -3+2

Step-by-step explanation:

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3 years ago
Which function is equivalent to the inverse of y=sec(x)
kipiarov [429]
From the identity:

sec(x)= \frac{1}{cos(x)}


f(x)=sec(x)= \frac{1}{cos(x)}

the inverse of f is g such that f(g(x))=x,

we must find g(x), such that \frac{1}{cos[g(x)]}=x

thus, cos[g(x)]= \frac{1}{x}

g(x)=cos^{-1} (\frac{1}{x})


Answer: b. g(x)=cos^-1(1/x)   
6 0
3 years ago
Dana is attaching a shelf to a wall and needs the shelf to be perpendicular to the wall. How many degrees should the shelf be re
KiRa [710]
90° because perpendicular lines are never ending.
8 0
3 years ago
Read 2 more answers
PLEASE HURRY :,) WILL GIVE BRAINLEST
Vlad1618 [11]

Answer:

Point R is at (-40,30),  a distance of 60 units from point Q

Step-by-step explanation:

<u>Explanation </u>

<u>we will use below conditions</u>

<u>Type of transformation</u>                                 <u> change to co-ordinate point</u>

  1. vertical translation up 'd' units                (x, y) changes to (x, y +d)
  2. vertical translation down 'd' units            (x, y) changes to (x, y-d)
  3. horizontal translation left 'c' units            (x, y)  changes to (x- c, y)  

   4. horizontal translation right 'c' units         (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

<u>Now we have to find 'R' point</u>

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is <u>vertical translation up '60' units </u>now changes the co-ordinate point is (-40 , -30+60)

<u>The correct translation and The point R( -40 , 30)</u>

<u>Step2:-</u>

Again in the given data  "R" is at the same distance from point Q as point P is from point Q.

<u>so given P point is (20 , -30)</u>

now we translation 'P' also

<u>vertically translation up at a distance '60' units</u> and changes the new co-ordinate (20 , -30+60) that is (20,30)  [ use above condition  is (1)]

and again<u> horizontal translation left '60</u>' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

<u>Final answer:-</u>

Point R is at (−40, 30), a distance of 60 units from point Q

6 0
3 years ago
How do I find the slope of this altitude?<br><br>I am referring to question 19.
Crazy boy [7]
The altitude's slope must be perpendicular to that of the line. 

The slope of segment BC is 2/5. The slope of the altitude must be perpendicular to 2/5. Since the negative reciprocal of 2/5 is -5/2, then the slope of the altitude is -5/2. 
6 0
3 years ago
Read 2 more answers
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