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maria [59]
3 years ago
9

What do conductivity and reactivity have in common

Chemistry
2 answers:
alexira [117]3 years ago
6 0
They both involve electrons.
7nadin3 [17]3 years ago
5 0

Explanation:

Conductivity is defined as the ability of a substance to freely flow the electrons from one point to another.

When electrons are able to flow freely through a material then it is considered a good conductor. But if electrons are not able to move freely then it is known as a bad conductor.

Whereas reactivity of a substance depends on the number of valence electrons present in it.

For example, alkali metals are highly reactive in nature due to the presence of  one valence electron.

Thus, we can conclude that both conductivity and reactivity have electrons in common.

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A 112 gram sample of an unknown metal was heated from 0.0C to 20.0C. The sample absorbed 1004 J of energy. What was the specific
worty [1.4K]

Answer:

The specific heat of the sample unknown metal is approximately 0.45 J/g °C.

General Formulas and Concepts:
<u>Thermodynamics</u>

Specific Heat Formula: \displaystyle q = mc \triangle T

  • <em>m</em> is mass (g)
  • <em>c</em> is specific heat capacity (J/g °C)
  • Δ<em>T</em> is the change in temperature

Explanation:

<u>Step 1: Define</u>

<em>Identify variables.</em>

<em>m</em> = 112 g

Δ<em>T</em> = 20.0 °C

<em>q</em> = 1004 J

<u>Step 2: Solve for </u><u><em>c</em></u>

  1. Substitute in variables [Specific Heat Formula]:                                        \displaystyle 1004 \ \text{J} = (112 \ \text{g})(c)(20.0 \ ^{\circ} \text{C})
  2. Simplify:                                                                                                        \displaystyle 1004 \ \text{J} = (2240 \ \text{g} \ ^\circ \text{C})c
  3. Isolate <em>c</em>:                                                                                                        \displaystyle c = 0.448214 \ \text{J} / \text{g} \ ^\circ \text{C}
  4. Round [Sig Figs]:                                                                                          \displaystyle c \approx 0.45 \ \text{J} / \text{g} \ ^\circ \text{C}

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.

---

Topic: AP Chemistry

Unit: Thermodynamics

5 0
3 years ago
Identify which one is the reducing agent in this reaction
Romashka-Z-Leto [24]

Answer:

Na.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
  • A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.

  • For the reaction:

<em>2Na + S → Na₂S.</em>

<em></em>

Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".

S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".

6 0
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Explanation:

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Answer:

the answer is 11.111 and when you round it to the nearest one it’s 11, but to the nearest tenth it’s 10

Explanation:

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14. הכניסו בקבוק מים במסה של 100 גר' לתוך מקפיא, מה מסתו של<br> הקרח לאחר שהמים קפאו ?
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Answer:

whattt, can u write it in English so i can help you

8 0
3 years ago
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