Answer:
The specific heat of the sample unknown metal is approximately 0.45 J/g °C.
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: 
- <em>m</em> is mass (g)
- <em>c</em> is specific heat capacity (J/g °C)
- Δ<em>T</em> is the change in temperature
Explanation:
<u>Step 1: Define</u>
<em>Identify variables.</em>
<em>m</em> = 112 g
Δ<em>T</em> = 20.0 °C
<em>q</em> = 1004 J
<u>Step 2: Solve for </u><u><em>c</em></u>
- Substitute in variables [Specific Heat Formula]:

- Simplify:

- Isolate <em>c</em>:

- Round [Sig Figs]:

∴ specific heat capacity <em>c</em> is equal to around 0.45 J/g °C.
---
Topic: AP Chemistry
Unit: Thermodynamics
Answer:
Na.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.
- A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.
<em>2Na + S → Na₂S.</em>
<em></em>
Na is oxidized to Na⁺ in (Na₂S) (loses 1 electron). "reducing agent".
S is reduced to S²⁻ in (Na₂S) (gains 2 electrons). "oxidizing agent".
Answer:
transfer pipet that had markings every 0.1 mL.
Explanation:
Answer:
the answer is 11.111 and when you round it to the nearest one it’s 11, but to the nearest tenth it’s 10
Explanation:
Answer:
whattt, can u write it in English so i can help you