PV=nRT
P= ? atm
V= 2 L
T= 423 K
n= 2.3 moles
R= 0.08205
(P)(2)=(2.3)(0.08205)(423)
P= (79.826445)/(2)
P= 39.9132225 atm
There are 0.5 moles of NaCl present in a 29.22g sample.
to find moles of a compound you would look at the periodic table to find the mass. in this case, the mass of NaCl is 58.44 g/mol. now, you divide the sample mass of 29.22g by 58.44 g/mol. the grams will cancel each other out and you’re left with 0.5 mol in that sample
hope this helps!
<span>If it is known that at 60 °C and 745 torr UF₆ is present only as a gas then we can make the assumption that:
</span>(n/V) = P/RT = (745 torr)/(62.36 L-torr/mol•K)(337 K) = 0.0354 mol/L
Therefore the density will be:
<span>
Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0125 g/cm³
</span>
Answer:
Last option is the correct choice.
Explanation:
Number of protons = 60-33 = 27
Superscript 60 Subscript 27 upper C o.
Best Regards!
