How many moles of sodium chloride are present in 1.0 l of a 5.5 m solution of sodium chloride in water?
2 answers:
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Answer:
Hexanoic acid is formed as insoluble product
Explanation:
- In aqueous sodium hydroxide, methyl ester of hexanoic acid hydrolyzes to produce soluble sodium hexanoate salt.
- Upon addition of aqueous HCl, hexanoate ion is protonated to produce hexanoic acid which is insoluble in water.
- Hence, upon acidification of hydrolysis solution, two separate layers (organic and aqueous) are formed.
- Reaction are shown below.
