In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
Answer:
It's 1/3.
Step-by-step explanation:
Common ratio = 9/27 = 1/3.
3 / 9 = 1/3
1 / 3 = 1/3 and so on.
Answer:
Here x=10° ,2x=20° ,5x=50°
Answer:
∠s = ∠v
Step-by-step explanation:
Supplementary angles add up to 180°
∠s + ∠v = 180
90 + ∠v = 180
∠v = 180 - 90
∠v = 90°
⇒∠s ≅ ∠v
