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Advocard [28]
3 years ago
11

Which ordered pair is on the graph of the function? O (-1,2) O (6,-3) O (-2,-4) O (-6, 4)​

Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

(6, -3)

Step-by-step explanation:

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Answer:

I got B too so I sure could be right answer but if it's not then I so sorry. B. 6

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Matteo is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli
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Answer: (1.5, 0)

Step-by-step explanation:

Given : The shape of his satellite can be modeled by y^2=6x where x and y are modeled in inches.

Now,the given equation y^2=6x is a equation of parabola.

Here, coefficient of x is positive, hence the parabola opens rightwards.

On comparing this equation with standard equation x^2=4mx, we get

4m=6\\\Rightarrow\ m=\frac{6}{4}=1.5

In standard equation, coordinates of focus=(m,0)

Thus for given equation coordinates of focus=(1.5,0)

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3 years ago
Question. 1 :
vovikov84 [41]
<h3>Answer to Question 1:</h3>

AB= 24cm

BC = 7cm

<B = 90°

AC = ?

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

AC^2 = 24^2 + 7^2

AC^2 = 576 + 49

AC^2 = √625

AC = 25

<h3>Answer to Question 2 :-</h3>

sin A = 3/4

CosA = ?

TanA = ?

<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>

(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)

<h3>Using Pythagoras theorem :-</h3>

AC^2 = AB^2 + BC ^ 2

4² = AB² + 3²

16 = AB + 9

AB = √7cm

<h3>CosA = Adjacent side/Hypotenuse</h3>

= AB/AC

= √7/4

<h3>TanA= Opp. side/Adjacent side</h3>

=BC/AB

= 3/√7

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2 years ago
Exercise 8.8. Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed betw
Nataliya [291]
The answers is 4:30 I hope it helps
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3 years ago
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