Answer:
I got B too so I sure could be right answer but if it's not then I so sorry. B. 6
Answer: (1.5, 0)
Step-by-step explanation:
Given : The shape of his satellite can be modeled by 
where x and y are modeled in inches.
Now,the given equation is a equation of parabola.
Here, coefficient of x is positive, hence the parabola opens rightwards.
On comparing this equation with standard equation 
, we get
In standard equation, coordinates of focus=(m,0)
Thus for given equation coordinates of focus=(1.5,0)
I think they should say they last name
<h3>Answer to Question 1:</h3>
AB= 24cm
BC = 7cm
<B = 90°
AC = ?
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
AC^2 = 24^2 + 7^2
AC^2 = 576 + 49
AC^2 = √625
AC = 25
<h3>Answer to Question 2 :-</h3>
sin A = 3/4
CosA = ?
TanA = ?
<h3>SinA = Opp. side/Hypotenuse</h3><h3> = 3/4</h3>
(Construct a triangle right angled at B with one side BC of 3cm and hypotenuse AC of 4cm.)
<h3>Using Pythagoras theorem :-</h3>
AC^2 = AB^2 + BC ^ 2
4² = AB² + 3²
16 = AB + 9
AB = √7cm
<h3>CosA = Adjacent side/Hypotenuse</h3>
= AB/AC
= √7/4
<h3>TanA= Opp. side/Adjacent side</h3>
=BC/AB
= 3/√7
