Solve: 12x^2+5x-4=12^2x+6

Mathematics

1 answer:

Orlov [11]3 years ago

4 0

Subtract the 12x^2 first.
5x - 4 = 6
Add the four
5x = 10
Then divide the 5 from both sides
X = 2

You might be interested in

A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation o

olasank [31]

Answer:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

Step-by-step explanation:

Information given

$\bar X=9.41$ represent the sample mean

$s=0.24$ represent the sample standard deviation

$n=81$ sample size

$\mu_o =9.33$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:

Null hypothesis: $\mu \leq 9.33$

Alternative hypothesis: $\mu > 9.33$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

4 0

3 years ago

Help!!!!! Not the top one by the way..!

OverLord2011 [107]

Answer:

$\large\boxed{x=-3\ and\ y=-11\to(-3,\ -11)}$

Step-by-step explanation:

$\underline{+\left\{\begin{array}{ccc}-6x+y=7\\3x-y=2\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad-3x=9\qquad\text{divide both sides by (-3)}\\.\qquad\boxed{x=-3}\\\\\text{Put the value of x to the first equation:}\\\\-6(-3)+y=7\\18+y=7\qquad\text{subtract 18 from both sides}\\\boxed{y=-11}$