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Dmitrij [34]
3 years ago
15

Find the range of the function f(x)=x2+5 given the domain (-2,-1,0,1,2)?

Mathematics
1 answer:
iren2701 [21]3 years ago
6 0

Answer:

(5, 6, 9)

Step-by-step explanation:

The domain is basically the set of all x values while the range is the set of all y values, in this case, it's the values of f(x). To find the range, we can plug the x values into the equation:

f(-2) = 9

f(-1) = 6

f(0) = 5

f(1) = 6

f(2) = 9

Since we can't have repeats in the range, it would be: (5, 6, 9)

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What is the simplified form of startroot startfraction 72 x superscript 16 baseline over 50 x superscript 36 baseline endfractio
ziro4ka [17]

The simplified form of the given equation is =\frac{6}{5x^{10}}

We have given that,

\sqrt{\frac{72x^{16}}{50x^{36} }

Apparently, you want to simplify the given equation,

\sqrt{\frac{72x^{16}}{50x^{36} }

 

The applicable rules of exponents are,

<h3>What is the exponent rule?</h3>

 (a^b)(a^c) = a^(b+c)

 1/a^b = a^(-b)

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So the expression simplifies as

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Therefore the simplified form of the given equation is =\frac{6}{5x^{10}}

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You can just add up the zeros, if that makes sense.

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